1.2*t^2-7t-300=0

Solution for 1.2*t^2-7t-300=0 equation:

1.2t^2-7t-300=0

a = 1.2; b = -7; c = -300;
Δ = b2-4ac
Δ = -72-4·1.2·(-300)
Δ = 1489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1489}}{2*1.2}=\frac{7-\sqrt{1489}}{2.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1489}}{2*1.2}=\frac{7+\sqrt{1489}}{2.4}
$